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Bismuth(III) iodide react with sulfuric acid

8BiI3 + 15H2SO4 → 4Bi2(SO4)3 + 12I2 + 3H2S + 12H2O




Bismuth(III) iodide react with sulfuric acid to produce bismuth(III) sulfate, iodine, hydrogen sulfide and water. Sulfuric acid - concentrated heated solution.


Picture of reaction: img1 BB html

Сoding to search: 8 BiI3 + 15 H2SO4 = 4 Bi2SO43 + 12 I2 + 3 H2S + 12 H2O

Add / Edited: 17.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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