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Bismuth(III) iodide react with iodine

BiI3 + 3I2 ⇄ Bi[I(I)2]3




Bismuth(III) iodide react with iodine to produce diiodoiodate(I) bismuth(III). The reaction takes place in a diluted solution hydrogen chloride.


Picture of reaction: img1 BB html

Сoding to search: BiI3 + 3 I2 = BiII23

Add / Edited: 17.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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