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Bromine(III) fluoride react with gold

4BrF3 + 2Au → 2Au[BrF6] + Br2




Bromine(III) fluoride react with gold to produce gold(I) hexafluorobromate(V) and bromine. This reaction takes place at a temperature near 40°C.


Picture of reaction: img1 BB html

Сoding to search: 4 BrF3 + 2 Au cnd [ temp ] = 2 AuBrF6 + Br2

Add / Edited: 24.02.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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