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Chlorine(I) fluoride react with rubidium fluoride

ClF + RbF → Rb[ClF2]




Chlorine(I) fluoride react with rubidium fluoride to produce rubidium difluorochlorate(I). This reaction takes place at a temperature near 175°C, and an overpressure.


Picture of reaction: img1 BB html

Сoding to search: ClF + RbF cnd [ temp ] = RbClF2

Add / Edited: 14.03.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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