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Boron chloride react with mercury

2BCl3 + 2Hg → B2Cl4 + Hg2Cl2

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Boron chloride react with mercury to produce tetradiboron chloride and mercury(I) chloride.

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Сoding to search: 2 BCl3 + 2 Hg = B2Cl4 + Hg2Cl2

Add / Edited: 30.09.2014 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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