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Copper(I) iodide react with nitric acid

2CuI + 8HNO3 → I2 + 2Cu(NO3)2 + 4NO2 + 4H2O




Copper(I) iodide react with nitric acid to produce copper nitrate, nitrogen dioxide and water. Nitric acid - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: 2 CuI + 8 HNO3 = I2 + 2 CuNO32 + 4 NO2 + 4 H2O

Add / Edited: 08.04.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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