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Copper(I) iodide react with sulfuric acid and iron(III) oxide

2CuI + 6H2SO4 + 2Fe2O3 → 2CuSO3 + 4FeSO4 + I2 + 6H2O




Copper(I) iodide react with sulfuric acid and iron(III) oxide to produce copper sulfate, iron(II) sulfate iodine and water. Sulfuric acid - concentrated solution. This reaction takes place at a temperature near 80°C.


Picture of reaction: img1 BB html

Сoding to search: 2 CuI + 6 H2SO4 + 2 Fe2O3 cnd [ temp ] = 2 CuSO3 + 4 FeSO4 + I2 + 6 H2O

Add / Edited: 08.04.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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