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Iron(II,III) oxide react with sodium hydroxide

Fe3O4 + 14NaOH → Na4FeO3 + 2Na5FeO4 + 7H2O




Iron(II,III) oxide react with sodium hydroxide to produce sodium ferrate(II), sodium ferrate(III) and water. This reaction takes place at a temperature of 400-500°C.


Picture of reaction: img1 BB html

Сoding to search: Fe3O4 + 14 NaOH cnd [ temp ] = Na4FeO3 + 2 Na5FeO4 + 7 H2O

Add / Edited: 18.04.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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