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Iron(II) iodide react with sulfuric acid and hydrogen peroxide

2FeI2 + 3H2SO4 + 3H2O2 → Fe2(SO4)3 + 2I2 + 6H2O




Iron(II) iodide react with sulfuric acid and hydrogen peroxide to produce iron(III) sulfate, iodine and water. Sulfuric acid - diluted solution. Hydrogen peroxide - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: 2 FeI2 + 3 H2SO4 + 3 H2O2 = Fe2SO43 + 2 I2 + 6 H2O

Add / Edited: 19.04.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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