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Iodine(I) bromide react with sodium hydroxide

3IBr + 6NaOH → 3NaBr + 2NaI + NaIO3 + 3H2O

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Iodine(I) bromide react with sodium hydroxide to produce sodium bromide, sodium iodide, sodium iodate and water. Sodium hydroxide - diluted solution.

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Сoding to search: 3 IBr + 6 NaOH = 3 NaBr + 2 NaI + NaIO3 + 3 H2O

Add / Edited: 18.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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