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Sodium iodide react with sulfuric acid

8NaI + 9H2SO4 → 4I2 + H2S + 8NaHSO4 + 4H2O




Sodium iodide react with sulfuric acid to produce iodine, hydrogen sulfide, sodium bisulfate and water. Sulfuric acid - concentrated solution. This reaction takes place at a temperature of 30-50°C.


Picture of reaction: img1 BB html

Сoding to search: 8 NaI + 9 H2SO4 cnd [ temp ] = 4 I2 + H2S + 8 NaHSO4 + 4 H2O

Add / Edited: 19.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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