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Iridium react with bromine(V) fluoride

Ir + 6BrF5 → 5IrF6 + 3Br2




Iridium react with bromine(V) fluoride to produce iridium(VI) fluoride and bromine. This reaction takes place at a temperature no more than 150°C.


Picture of reaction: img1 BB html

Сoding to search: Ir + 6 BrF5 cnd [ temp ] = 5 IrF6 + 3 Br2

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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