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Iridium react with potassium bisulfate

2Ir + 6KHSO4 → 2K3[Ir(SO4)3] + 3H2




Iridium react with potassium bisulfate to produce trisulfatoiridate(III) potassium and hydrogen. This reaction takes place at a temperature of 300-400°C. Impurities: - oxide sulfur(IV) SO2.


Picture of reaction: img1 BB html

Сoding to search: 2 Ir + 6 KHSO4 cnd [ temp ] = 2 K3IrSO43 + 3 H2

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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