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Iridium react with carbon monoxide
4Ir + 12CO
[Ir
4
(CO)
12
]
[ Check the balance ]
Iridium react with carbon monoxide to produce dodecarbonyltetrairidium. This reaction takes place at a temperature near 150°C and an overpressure. In this reaction, the catalyst is can be copper.
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Picture of reaction:
Сoding to search:
4 Ir + 12 CO cnd [ temp ] = Ir4CO12
Add / Edited:
31.05.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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