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Iridium react with carbon monoxide

4Ir + 12CO → [Ir4(CO)12]

Iridium react with carbon monoxide to produce dodecarbonyltetrairidium. This reaction takes place at a temperature near 150°C and an overpressure. In this reaction, the catalyst is can be copper.

Picture of reaction: img1 BB html

Сoding to search: 4 Ir + 12 CO cnd [ temp ] = Ir4CO12

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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