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Oktacarbonyldiiridium react with sodium amalgam

[Ir2(CO)8] + 2(Na,Hg) → 2Na[Ir(CO)4] + 2Hg




Oktacarbonyldiiridium react with sodium amalgam to produce sodium tetracarbonyliridate and mercury. This reaction takes place in a hexane.


Picture of reaction: img1 BB html

Сoding to search: Ir2CO8 + 2 Na,Hg = 2 NaIrCO4 + 2 Hg

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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