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Iridium(III) chloride react with sodium hydroxide

2IrCl3 + 6NaOH → Ir2O3 + 6NaCl + 3H2O




Iridium(III) chloride react with sodium hydroxide to produce oxide iridium(III), sodium chloride and water. Sodium hydroxide - diluted solution.


Picture of reaction: img1 BB html

Сoding to search: 2 IrCl3 + 6 NaOH = Ir2O3 + 6 NaCl + 3 H2O

Add / Edited: 31.05.2015 /

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