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Iridium(III) chloride react with sodium hydroxide and oxygen

4IrCl3 + 12NaOH + O2 → 4IrO2 + 12NaCl + H2O




Iridium(III) chloride react with sodium hydroxide and oxygen to produce iridium(IV) oxide, sodium chloride and water. Sodium hydroxide - diluted solution. This reaction takes place slowly.


Picture of reaction: img1 BB html

Сoding to search: 4 IrCl3 + 12 NaOH + O2 = 4 IrO2 + 12 NaCl + H2O

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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