IrCl3 + NaOH + O2 = IrO2 + NaCl + H2O |

4IrCl₃ + 12NaOH + O₂ → 4IrO₂ + 12NaCl + H₂O

Iridium(III) chloride react with sodium hydroxide and oxygen to produce iridium(IV) oxide, sodium chloride and water. Sodium hydroxide - diluted solution. This reaction takes place slowly.

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Iridium(III) chloride react with sodium hydroxide and oxygen

4IrCl₃ + 12NaOH + O₂ → 4IrO₂ + 12NaCl + H₂O

Picture of reaction:

Сoding to search: 4 IrCl3 + 12 NaOH + O2 = 4 IrO2 + 12 NaCl + H2O

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Iridium(III) chloride react with sodium hydroxide and oxygen

4IrCl3 + 12NaOH + O2 → 4IrO2 + 12NaCl + H2O

Picture of reaction:

Сoding to search: 4 IrCl3 + 12 NaOH + O2 = 4 IrO2 + 12 NaCl + H2O

Add / Edited: 31.05.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4IrCl₃ + 12NaOH + O₂ → 4IrO₂ + 12NaCl + H₂O

Add / Edited: 31.05.2015 /