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Iridium(III) chloride react with sodium cyclopentadienyl and cyclopentadiene

IrCl3 + Na(C5H5) + C5H6 → [Ir(C5H6)C5H5] + NaCl + Cl2




Iridium(III) chloride react with sodium cyclopentadienyl and cyclopentadiene to produce cyclopentadienylcyclopentadieneiridium, sodium chloride and chlorine. cyclopentadiene - liquid. The reaction proceeds at room temperature.


Picture of reaction: img1 BB html

Сoding to search: IrCl3 + NaC5H5 + C5H6 = IrC5H6C5H5 + NaCl + Cl2

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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