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Iridium(IV) chloride react with sodium chloride

IrCl4 + 2NaCl → Na2[IrCl6]




Iridium(IV) chloride react with sodium chloride to produce sodium hexachloridoiridate(IV). Sodium chloride - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: IrCl4 + 2 NaCl = Na2IrCl6

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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