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Iridium(IV) chloride react with ammonium hydroxide, sodium hydroxide and sodium hypophosphite

2IrCl4 + 10(NH3•H2O) + 3NaOH + NaH2PO2 → 2[Ir(H2O)(NH3)5]Cl3 + Na2HPO3 + 2NaCl + 10H2O




Iridium(IV) chloride react with ammonium hydroxide, sodium hydroxide and sodium hypophosphite to produce pentaammineaquairidium(III) chloride, disodium hydrogen phosphite, sodium chloride and water. Ammonium hydroxide - concentrated solution. Sodium hydroxide - diluted solution.


Picture of reaction: img1 BB html

Сoding to search: 2 IrCl4 + 10 NH3 • H2O + 3 NaOH + NaH2PO2 = 2 IrH2ONH35Cl3 + Na2HPO3 + 2 NaCl + 10 H2O

Add / Edited: 31.05.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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