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Sodium hexachloridoiridate(III) react with sodium hydroxide and oxygen

4Na3[IrCl6] + 12NaOH + O2 → 4IrO2 + 24NaCl + 6H2O




Sodium hexachloridoiridate(III) react with sodium hydroxide and oxygen to produce iridium(IV) oxide, sodium chloride and water. This reaction slowly takes place on air.


Picture of reaction: img1 BB html

Сoding to search: 4 Na3IrCl6 + 12 NaOH + O2 = 4 IrO2 + 24 NaCl + 6 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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