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Iridium(IV) fluoride react with sodium hydroxide

4IrF4 + 16NaOH → 2Ir2O3 + O2 + 16NaF + 8H2O




Iridium(IV) fluoride react with sodium hydroxide to produce oxide iridium(III), oxygen, sodium fluoride and water. Sodium hydroxide - concentrated solution.


Picture of reaction: img1 BB html

Сoding to search: 4 IrF4 + 16 NaOH = 2 Ir2O3 + O2 + 16 NaF + 8 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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