IrF4 + NaOH = Ir2O3 + O2 + NaF + H2O |

4IrF₄ + 16NaOH → 2Ir₂O₃ + O₂ + 16NaF + 8H₂O

Iridium(IV) fluoride react with sodium hydroxide to produce oxide iridium(III), oxygen, sodium fluoride and water. Sodium hydroxide - concentrated solution.

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Iridium(IV) fluoride react with sodium hydroxide

4IrF₄ + 16NaOH → 2Ir₂O₃ + O₂ + 16NaF + 8H₂O

Picture of reaction:

Сoding to search: 4 IrF4 + 16 NaOH = 2 Ir2O3 + O2 + 16 NaF + 8 H2O

Add / Edited: 01.06.2015 /

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Iridium(IV) fluoride react with sodium hydroxide

4IrF4 + 16NaOH → 2Ir2O3 + O2 + 16NaF + 8H2O

Picture of reaction:

Сoding to search: 4 IrF4 + 16 NaOH = 2 Ir2O3 + O2 + 16 NaF + 8 H2O

Add / Edited: 01.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

4IrF₄ + 16NaOH → 2Ir₂O₃ + O₂ + 16NaF + 8H₂O

Add / Edited: 01.06.2015 /