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Iridium(IV) fluoride react with lithium fluoride

IrF4 + 2LiF → Li2[IrF6]




Iridium(IV) fluoride react with lithium fluoride to produce lithium hexafluoroiridate(IV). This reaction takes place at a temperature near 200°C.


Picture of reaction: img1 BB html

Сoding to search: IrF4 + 2 LiF cnd [ temp ] = Li2IrF6

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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