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Chemical reactions
Сhemical tables
Iridium(IV) fluoride react with ammonium fluoride
IrF
4
+ 2NH
4
F
(NH
4
)
2
[IrF
6
]
[ Check the balance ]
Iridium(IV) fluoride react with ammonium fluoride to produce ammonium hexafluoroiridate(IV). This reaction takes place at a temperature near 200°C.
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Picture of reaction:
Сoding to search:
IrF4 + 2 NH4F cnd [ temp ] = NH42IrF6
Add / Edited:
01.06.2015 /
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