Home Reactions
Language: ru en
Log in:

Iridium(IV) fluoride react with ammonium fluoride

IrF4 + 2NH4F → (NH4)2[IrF6]




Iridium(IV) fluoride react with ammonium fluoride to produce ammonium hexafluoroiridate(IV). This reaction takes place at a temperature near 200°C.


Picture of reaction: img1 BB html

Сoding to search: IrF4 + 2 NH4F cnd [ temp ] = NH42IrF6

Add / Edited: 01.06.2015 /

Evaluation of information: 0.0 out of 5 / number of votes: 0


Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | VK page
ChemiDay.com © 2016