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Iridium(V) fluoride react with sodium hydroxide

4IrF5 + 20NaOH → 4IrO2 + 20NaF + O2 + 10H2O

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Iridium(V) fluoride react with sodium hydroxide to produce iridium(IV) oxide, sodium fluoride oxygen and water. Sodium hydroxide - diluted solution.

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Сoding to search: 4 IrF5 + 20 NaOH = 4 IrO2 + 20 NaF + O2 + 10 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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