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Iridium(VI) fluoride react with sodium hydroxide

2IrF6 + 12NaOH → 2IrO2 + O2 + 12NaF + 6H2O




Iridium(VI) fluoride react with sodium hydroxide to produce iridium(IV) oxide, oxygen, sodium fluoride and water. Sodium hydroxide - diluted solution.


Picture of reaction: img1 BB html

Сoding to search: 2 IrF6 + 12 NaOH = 2 IrO2 + O2 + 12 NaF + 6 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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