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Iridium(III) oxide react with nitric acid

Ir2O3 + 2HNO3 → 2IrO2 + 2NO2 + H2O




Iridium(III) oxide react with nitric acid to produce iridium(IV) oxide, nitrogen dioxide and water. The reaction takes place in a boiling solution.


Picture of reaction: img1 BB html

Сoding to search: Ir2O3 + 2 HNO3 = 2 IrO2 + 2 NO2 + H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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