Ir2(SO4)3 + HNO3 + H2O = IrO2 + NO2 + H2SO4 |

Ir₂(SO₄)₃ + 2HNO₃ + 2H₂O → 2IrO₂ + 2NO₂ + 3H₂SO₄

Iridium(III) sulfate react with nitric acid and water to produce iridium(IV) oxide, nitrogen dioxide and sulfuric acid. Nitric acid - concentrated solution. The reaction takes place in a boiling solution.

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Iridium(III) sulfate react with nitric acid and water

Ir₂(SO₄)₃ + 2HNO₃ + 2H₂O → 2IrO₂ + 2NO₂ + 3H₂SO₄

Picture of reaction:

Сoding to search: Ir2SO43 + 2 HNO3 + 2 H2O = 2 IrO2 + 2 NO2 + 3 H2SO4

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

Iridium(III) sulfate react with nitric acid and water

Ir2(SO4)3 + 2HNO3 + 2H2O → 2IrO2 + 2NO2 + 3H2SO4

Picture of reaction:

Сoding to search: Ir2SO43 + 2 HNO3 + 2 H2O = 2 IrO2 + 2 NO2 + 3 H2SO4

Add / Edited: 01.06.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

Ir₂(SO₄)₃ + 2HNO₃ + 2H₂O → 2IrO₂ + 2NO₂ + 3H₂SO₄

Add / Edited: 01.06.2015 /