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Iridium(III) sulfate react with sodium hydroxide

Ir2(SO4)3 + 6NaOH → Ir2O3 + 3Na2SO4 + 3H2O




Iridium(III) sulfate react with sodium hydroxide to produce oxide iridium(III), sodium sulfate and water. Sodium hydroxide - diluted solution.


Picture of reaction: img1 BB html

Сoding to search: Ir2SO43 + 6 NaOH = Ir2O3 + 3 Na2SO4 + 3 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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