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Iridium(III) sulfate react with sodium hydroxide and oxygen

2Ir2(SO4)3 + 12NaOH + O2 → 4IrO2 + 6Na2SO4 + 6H2O


Iridium(III) sulfate react with sodium hydroxide and oxygen to produce iridium(IV) oxide, sodium sulfate and water. Sodium hydroxide - diluted solution. This reaction slowly takes place on air.


Picture of reaction: img1 BB html

Сoding to search: 2 Ir2SO43 + 12 NaOH + O2 = 4 IrO2 + 6 Na2SO4 + 6 H2O

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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