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Iridium(III) sulfate react with oxalic acid

Ir2(SO4)3 + 6H2C2O4 → 2H3[Ir(C2O4)3] + 3H2SO4




Iridium(III) sulfate react with oxalic acid to produce hydrogen trioxalatoiridate(III) and sulfuric acid. Oxalic acid - concentrated, cold solution.


Picture of reaction: img1 BB html

Сoding to search: Ir2SO43 + 6 H2C2O4 = 2 H3IrC2O43 + 3 H2SO4

Add / Edited: 01.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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