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Lead(IV) oxide react with potassium iodide and nitric acid

PbO2 + 2KI + 4HNO3 → I2 + Pb(NO3)2 + 2KNO3 + 2H2O




Lead(IV) oxide react with potassium iodide and nitric acid to produce iodine, lead(II) nitrate, potassium nitrate and water. Nitric acid - diluted solution. The reaction proceeds at room temperature.


Picture of reaction: img1 BB html

Сoding to search: PbO2 + 2 KI + 4 HNO3 = I2 + PbNO32 + 2 KNO3 + 2 H2O

Add / Edited: 05.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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