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Lanthanum react with oxide samarium(III)

2La + Sm2O3 → La2O3 + 2Sm




Lanthanum react with oxide samarium(III) to produce lanthanum(III) oxide and samarium. This reaction takes place at a temperature of 1100-1200°C.


Picture of reaction: img1 BB html

Сoding to search: 2 La + Sm2O3 = La2O3 + 2 Sm

Add / Edited: 10.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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