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Lithium iodide react with sulfuric acid

8LiI + 5H2SO4 → 4I2 + H2S + 4Li2SO4 + 4H2O




Lithium iodide react with sulfuric acid to produce iodine, hydrogen sulfide, lithium sulfate and water. Lithium iodide - solid. Sulfuric acid - concentrated solution. The reaction takes place in a boiling solution.


Picture of reaction: img1 BB html

Сoding to search: 8 LiI + 5 H2SO4 = 4 I2 + H2S + 4 Li2SO4 + 4 H2O

Add / Edited: 12.06.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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