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Potassium hexachloridoplatinate(IV) react with potassium iodide

K2[PtCl6] + 5KI → PtI2 + K[I(I)2] + 6KCl


Potassium hexachloridoplatinate(IV) react with potassium iodide to produce platinum(II) iodide potassium diiodoiodate(I) and potassium chloride. Potassium iodide - concentrated solution. This reaction takes place at a temperature near 60°C.


Picture of reaction: img1 BB html

Сoding to search: K2PtCl6 + 5 KI cnd [ temp ] = PtI2 + KII2 + 6 KCl

Add / Edited: 13.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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