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Potassium hexachloridoplatinate(IV) react with chlorine(III) fluoride

K2[PtCl6] + 2ClF3 → K2[PtF6] + 4Cl2




Potassium hexachloridoplatinate(IV) react with chlorine(III) fluoride to produce potassium hexafluoroplatinate(IV) and chlorine. This reaction takes place at a temperature near 500°C.


Picture of reaction: img1 BB html

Сoding to search: K2PtCl6 + 2 ClF3 cnd [ temp ] = K2PtF6 + 4 Cl2

Add / Edited: 13.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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