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Platinum(I) fluoride react with xenon difluoride

2PtF4 + 7XeF2 → 2(XeF5)[PtF6] + 5Xe

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Platinum(I) fluoride react with xenon difluoride to produce pentafluoroxenon(VI) hexafluoroplatinate(V). The reaction proceeds at room temperature.

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Сoding to search: 2 PtF4 + 7 XeF2 = 2 XeF5PtF6 + 5 Xe

Add / Edited: 13.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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