ZrO(OH)2 = ZrO2 + H2O |

ZrO(OH)₂ ZrO₂ + H₂O

The thermal decomposition of zirconium(IV) dihydroxide-oxide to produce zirconium(IV) oxide and water. This reaction takes place at a temperature of 300-600°C.

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The thermal decomposition of zirconium(IV) dihydroxide-oxide

ZrO(OH)₂ ZrO₂ + H₂O

Picture of reaction:

Сoding to search: ZrOOH2 cnd [ temp ] = ZrO2 + H2O

Add / Edited: 14.07.2015 /

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The thermal decomposition of zirconium(IV) dihydroxide-oxide

ZrO(OH)2 ZrO2 + H2O

Picture of reaction:

Сoding to search: ZrOOH2 cnd [ temp ] = ZrO2 + H2O

Add / Edited: 14.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

ZrO(OH)₂ ZrO₂ + H₂O

Add / Edited: 14.07.2015 /