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Zirconium(IV) dihydroxide-oxide react with sulfuric acid

ZrO(OH)2 + 2H2SO4 → Zr(SO4)2 + 3H2O

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Zirconium(IV) dihydroxide-oxide react with sulfuric acid to produce zirconium(IV) sulfate and water. Sulfuric acid - 60% solution.

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Сoding to search: ZrOOH2 + 2 H2SO4 = ZrSO42 + 3 H2O

Add / Edited: 14.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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