Home Reactions Blog
Language: ru es en
Chemiday Log in:

Zirconium(IV) dihydroxide-oxide react with sodium hydroxide and water

ZrO(OH)2 + NaOH + 4H2O ⇄ Na[Zr(H2O)3(OH)5]


Zirconium(IV) dihydroxide-oxide react with sodium hydroxide and water to produce sodium pentahydroxotriaquazirconate(IV). Sodium hydroxide - 30% solution.


Picture of reaction: img1 BB html

Сoding to search: ZrOOH2 + NaOH + 4 H2O = NaZrH2O3OH5

Add / Edited: 14.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


Please register to post comments
ChemiDay you always could choose go nuts or keep calm with us or without.
About | Feedback and suggestions | Contact us | VK page
ChemiDay.com © 2022
Cookies policy, User agreement, Privacy policy.