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Zirconium(IV) dihydroxide-oxide react with sodium hydroxide and water

ZrO(OH)2 + 2NaOH + H2O ⇄ Na2[Zr(OH)6]


Zirconium(IV) dihydroxide-oxide react with sodium hydroxide and water to produce sodium hexahydroxozirconate(IV). Sodium hydroxide - 40% solution.

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Сoding to search: ZrOOH2 + 2 NaOH + H2O = Na2ZrOH6

Add / Edited: 14.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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