ZrO2•nH2O = ZrO(OH)2 + H2O |

ZrO₂•nH₂O ZrO(OH)₂ + (n-1)H₂O

The thermal decomposition of hydrate zirconium(IV) oxide to produce zirconium(IV) dihydroxide-oxide and water. This reaction takes place at a temperature near 140°C.

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The thermal decomposition of hydrate zirconium(IV) oxide

ZrO₂•nH₂O ZrO(OH)₂ + (n-1)H₂O

Picture of reaction:

Сoding to search: ZrO2 • nH2O cnd [ temp ] = ZrOOH2 + n-1 H2O

Add / Edited: 14.07.2015 /

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The thermal decomposition of hydrate zirconium(IV) oxide

ZrO2•nH2O ZrO(OH)2 + (n-1)H2O

Picture of reaction:

Сoding to search: ZrO2 • nH2O cnd [ temp ] = ZrOOH2 + n-1 H2O

Add / Edited: 14.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

ZrO₂•nH₂O ZrO(OH)₂ + (n-1)H₂O

Add / Edited: 14.07.2015 /