ZrI4 + H2SO4 = H2[Zr(SO4)2O] + I2 + SO2 + H2O |

ZrI₄ + 4H₂SO₄ → H₂[Zr(SO₄)₂O] + 2I₂ + 2SO₂ + 3H₂O

Zirconium(IV) iodide react with sulfuric acid to produce hydrogen oxodisulfatozirconate(IV), iodine, sulfur dioxide and water. Sulfuric acid - concentrated solution.

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Zirconium(IV) iodide react with sulfuric acid

ZrI₄ + 4H₂SO₄ → H₂[Zr(SO₄)₂O] + 2I₂ + 2SO₂ + 3H₂O

Picture of reaction:

Сoding to search: ZrI4 + 4 H2SO4 = H2ZrSO42O + 2 I2 + 2 SO2 + 3 H2O

Add / Edited: 14.07.2015 /

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Zirconium(IV) iodide react with sulfuric acid

ZrI4 + 4H2SO4 → H2[Zr(SO4)2O] + 2I2 + 2SO2 + 3H2O

Picture of reaction:

Сoding to search: ZrI4 + 4 H2SO4 = H2ZrSO42O + 2 I2 + 2 SO2 + 3 H2O

Add / Edited: 14.07.2015 / document.write(dtm['day']+'.'+dtm['mon']+'.'+dtm['year'])

ZrI₄ + 4H₂SO₄ → H₂[Zr(SO₄)₂O] + 2I₂ + 2SO₂ + 3H₂O

Add / Edited: 14.07.2015 /