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Zirconium(II) iodide react with ammonia

2ZrI4 + 2NH3 → 2ZrN + 3H2 + 4I2

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Zirconium(II) iodide react with ammonia to produce zirconium nitride, hydrogen and iodine. This reaction takes place at a temperature near 1000°C.

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Сoding to search: 2 ZrI4 + 2 NH3 cnd [ temp ] = 2 ZrN + 3 H2 + 4 I2

Add / Edited: 14.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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