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Zirconium(IV) fluoride react with cesium fluoride

ZrF4 + 2CsF → Cs2[ZrF6]


Zirconium(IV) fluoride react with cesium fluoride to produce cesium hexafluorozirconate(IV). This reaction takes place at a temperature of 700-900°C.


Picture of reaction: img1 BB html

Сoding to search: ZrF4 + 2 CsF cnd [ temp ] = Cs2ZrF6

Add / Edited: 15.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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