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Zirconium(IV) chloride react with boron bromide

3ZrCl4 + 4BBr3 → 3ZrBr4 + 4BCl3

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Zirconium(IV) chloride react with boron bromide to produce zirconium(IV) bromide and boron chloride. This reaction takes place at a temperature of 90-110°C.

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Сoding to search: 3 ZrCl4 + 4 BBr3 cnd [ temp ] = 3 ZrBr4 + 4 BCl3

Add / Edited: 15.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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