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Zirconium(IV) chloride react with aluminum iodide

3ZrCl4 + 4AlI3 → 3ZrI4 + 4AlCl3

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Zirconium(IV) chloride react with aluminum iodide to produce zirconium(IV) iodide and aluminum chloride. This reaction takes place at a temperature of 200-250°C.

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Сoding to search: 3 ZrCl4 + 4 AlI3 cnd [ temp ] = 3 ZrI4 + 4 AlCl3

Add / Edited: 15.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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