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Electrolysis melt of rubidium hydroxide

4RbOH ± 4e- → 4Rb + O2 + 2H2O

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Electrolysis melt of rubidium hydroxide to produce rubidium, oxygen and water.
  • Cathodic process: 4Rb+ + 4e- → 4Rb
  • Anodic process: 4OH- - 4e- → O2 + 2H2O

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Picture of reaction: img1 BB html

Сoding to search: 4 RbOH cnd [ temp electro ] = 4 Rb + O2 + 2 H2O

Add / Edited: 17.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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