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Zinc iodide react with ammonia

ZnI2 + 6NH3 → [Zn(NH3)6]I2


Zinc iodide react with ammonia to produce hexaamminezinc(II) iodide. The reaction is conducted in a liquid ammonia, at a temperature near -40°C.

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Picture of reaction: img1 BB html

Сoding to search: ZnI2 + 6 NH3 = ZnNH36I2

Add / Edited: 18.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1


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