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Zinc iodide react with lithium tetrahydroxoaluminate(III)

ZnI2 + 2Li[AlH4] → ZnH2 + 2AlH3 + 2LiI

Zinc iodide react with lithium tetrahydroxoaluminate(III) to produce zinc hydride, aluminum hydride and lithium iodide. This reaction takes place in the medium of ester, at a temperature near -40°C.

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Сoding to search: ZnI2 + 2 LiAlH4 = ZnH2 + 2 AlH3 + 2 LiI

Add / Edited: 18.07.2015 /

Evaluation of information: 5.0 out of 5 / number of votes: 1

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