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Zinc iodide react with lithium tetrahydroxoaluminate(III)
ZnI
2
+ 2Li[AlH
4
] → ZnH
2
+ 2AlH
3
+ 2LiI
[ Check the balance ]
Zinc iodide react with lithium tetrahydroxoaluminate(III) to produce zinc hydride, aluminum hydride and lithium iodide. This reaction takes place in the medium of ester, at a temperature near -40°C.
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Picture of reaction:
Сoding to search:
ZnI2 + 2 LiAlH4 = ZnH2 + 2 AlH3 + 2 LiI
Add / Edited:
18.07.2015 /
Evaluation of information:
5.0 out of 5 / number of votes: 1
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